DRAW LOCUS OF POINT SO THAT IT IS EQUIDISTANT FROM BC & CA . ... constructed such that none of these triangles overlaps triangle ABC. a) Draw a triangle ABC and then sketch ... 16) AB = 3.2cm BC = 8.4cm The area of the triangle ABC is 10cm². ... CONSTRUCT ANGLE ABC WHERE AB=AC=10cm AND BC=9cm
2 answers
if BC and CA are lines, then the locus of points equidistant from both lines is the bisector of the angle between them.
If24 is division 2