Ricardo's present age --- x
Dorothy's present age --- x+6
product of their present ages = x(x+6)
6 years ago:
Ricardo x-6
Dorothy x
product of their ages then = x(x-6)
x(x+6) = 2x(x-6)
solve for x, sub into x+6
Dorthy is 6 years older than Ricardo. The product of their present age is twice what the product of their ages was 6 years ago. How old is Dorthy?
2 answers
Let D=age of Dorthy.
" Dorthy is 6 years older than Ricardo. "
Age of Ricardo = D-6
"The product of their present age"
D(D-6)
"is twice what the product of their ages was 6 years ago"
=2*((D-6)*(D-6-6))
Thus
D(D-6) = 2*((D-6)*(D-12))
Simplify and solve for D and reject the solution of D=6 because it is a trivial solution. Check the answer by substitution into problem data.
" Dorthy is 6 years older than Ricardo. "
Age of Ricardo = D-6
"The product of their present age"
D(D-6)
"is twice what the product of their ages was 6 years ago"
=2*((D-6)*(D-6-6))
Thus
D(D-6) = 2*((D-6)*(D-12))
Simplify and solve for D and reject the solution of D=6 because it is a trivial solution. Check the answer by substitution into problem data.