Does this:
sqrt 3x-4=(x-4)^2-3
Multiply out to:
x^4-16x^3+90x^2-111x+173
Once I know it is multiplied out right then I can continue. Thanks
5 answers
i got 3x^2-16x+16
no
first of all, you don't have an equation as your answer.
√(3x-4)=(x-4)^2-3
square both sides
3x-4 = (x-4)^4 - 6(x-4)^2 + 9
3x - 4 = x^4 - 16x^3 + 96x^2 - 256x + 256 - 6x^2 + 48x - 96 + 9
x^4 - 16x^3 + 102x^2 - 211x + 166 = 0
first of all, you don't have an equation as your answer.
√(3x-4)=(x-4)^2-3
square both sides
3x-4 = (x-4)^4 - 6(x-4)^2 + 9
3x - 4 = x^4 - 16x^3 + 96x^2 - 256x + 256 - 6x^2 + 48x - 96 + 9
x^4 - 16x^3 + 102x^2 - 211x + 166 = 0
Oh thanks didn't see this post.
I realized I needed to make it equal zero. I keep getting 90 x^2 instead of 102 and 173 instead of 166.
Why do they make this so hard?
I realized I needed to make it equal zero. I keep getting 90 x^2 instead of 102 and 173 instead of 166.
Why do they make this so hard?
the difficulty is that you have to square the whole side, not just each term.
I agree with you, that is a hard question at your level.
Solving the final equation would be a nightmare.
I agree with you, that is a hard question at your level.
Solving the final equation would be a nightmare.
I'm looking at your solution and I can't figure out where that -6 came from.
1 answer