Question
Do the following side lengths satisfy the Pythagorean Theorem? Lengths =14, 50, 48.
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GPT-4o mini
To determine if the side lengths 14, 50, and 48 satisfy the Pythagorean Theorem, we need to check if the equation \(a^2 + b^2 = c^2\) holds true, where \(c\) is the longest side.
First, identify the longest side:
- The longest side is 50.
Now, we will assign the lengths:
- \(a = 14\)
- \(b = 48\)
- \(c = 50\)
Next, we calculate \(a^2 + b^2\) and \(c^2\):
1. Calculate \(a^2\) and \(b^2\):
\[
a^2 = 14^2 = 196
\]
\[
b^2 = 48^2 = 2304
\]
2. Now add them together:
\[
a^2 + b^2 = 196 + 2304 = 2500
\]
3. Now calculate \(c^2\):
\[
c^2 = 50^2 = 2500
\]
Now we compare \(a^2 + b^2\) and \(c^2\):
\[
a^2 + b^2 = 2500 \quad \text{and} \quad c^2 = 2500
\]
Since \(a^2 + b^2 = c^2\), the sides 14, 50, and 48 satisfy the Pythagorean Theorem.
First, identify the longest side:
- The longest side is 50.
Now, we will assign the lengths:
- \(a = 14\)
- \(b = 48\)
- \(c = 50\)
Next, we calculate \(a^2 + b^2\) and \(c^2\):
1. Calculate \(a^2\) and \(b^2\):
\[
a^2 = 14^2 = 196
\]
\[
b^2 = 48^2 = 2304
\]
2. Now add them together:
\[
a^2 + b^2 = 196 + 2304 = 2500
\]
3. Now calculate \(c^2\):
\[
c^2 = 50^2 = 2500
\]
Now we compare \(a^2 + b^2\) and \(c^2\):
\[
a^2 + b^2 = 2500 \quad \text{and} \quad c^2 = 2500
\]
Since \(a^2 + b^2 = c^2\), the sides 14, 50, and 48 satisfy the Pythagorean Theorem.
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