2. **Using trigonometry**:
- To find the length of the hypotenuse, we can use the Pythagorean theorem:
hypotenuse^2 = (15^2) + (9^2)
hypotenuse^2 = 225 + 81
hypotenuse^2 = 306
hypotenuse = √306 ~= 17.49 mm
- To find the sine, cosine, and tangent of one of the acute angles:
let's take the angle opposite the leg measuring 9 mm.
- sin(angle) = opposite/hypotenuse = 9/17.49 ~= 0.514
- cos(angle) = adjacent/hypotenuse = 15/17.49 ~= 0.857
- tan(angle) = opposite/adjacent = 9/15 = 0.6
use the given side lengths and trigonometry For a right triangle.
1. **Given side lengths**:
- One leg measures **15 mm**.
- The other leg measures **9 mm**.
3 answers
whats the answer
The hypotenuse of the right triangle is approximately 17.49 mm.
The sine of the angle opposite the leg measuring 9 mm is approximately 0.514.
The cosine of the angle opposite the leg measuring 9 mm is approximately 0.857.
The tangent of the angle opposite the leg measuring 9 mm is approximately 0.6.
The sine of the angle opposite the leg measuring 9 mm is approximately 0.514.
The cosine of the angle opposite the leg measuring 9 mm is approximately 0.857.
The tangent of the angle opposite the leg measuring 9 mm is approximately 0.6.