divide and simplify

Question

(y^3-3y)/(y^2-9)divided by
(y^2-7y-30)/(y^2+6y+9)

Please help!

Answer 1

(y^3-3y)/(y^2-9)*(y^2+6y+9)/(y^2-7y-30)=
(y(y^2-3)/(y+3)(y-3))*(y+3)(y+3)/(y+3)(y-10)=((y^2-3)/(y-3)*1/(y-10)=
(y^2-3)/(y-3)(y-10)

NOTE: All "(y+3)s" cancelled.