Divide 3n^2-n/n^2-1/n^2/n+1

2 answers

You are unlikely to get a reply if you are not clear about what are the various numerators and denominators. Do you mean what you typed or:

(3n^2-n)/(n^2-1)/(n^2)/(n+1 )
If it is as I typed it:

[ (3n^2-n)/(n^2-1) ]/ [(n^2)/(n+1 ) ]

[ (3n^2-n)/{n+1)(n-1) } ]/ [(n^2)/(n+1 ) ]

[ (3n^2-n)/(n-1) } ]/ [(n^2)/ ]

[ (3n^2-n)/(n-1) } ]/ [(n^2)/ ]

[ (3n-1)/(n-1) } ]/ [(n) ]

(3n-1) / (n^2-n)