Divide 3n^2-n/n^2-1/n^2/n+1

3 answers

I am having trouble figuring out the problem. Could you re-enter it with ( ) for things that go together or tell me if I am right..

I am reading this as (3n^2-n)/(n^2-1)/(n^2)/(n+1)
Can't re-enter because that's how it 's written.
Where did you get it written like that?

On paper is it fraction over fraction over fraction over fraction?

If so, when you enter it here, you need ( ) for each separate part of the fraction otherwise it could be interpreted as

3n^2 subtract n divided by n^2 etc.