y=( (8x-x^6)(x^-3) )^-4/5
y= ( (8x-2 -x^3) )-4/5
y'= -4/5 (8x^-2 -x^-6)^-9/5 * (-16x+6x^5)
I don't think this is the same answer. Check both.
Differentiate
y=[(8x-x^6)/(x^3)]^(-4/5)
My answer:
[4x^3(16+3x^5)]/5 • fifth root of [(8x-x^6)/(x^3)] ^9
2 answers
the radicand is a fraction, not a product.
y = [(8x-x^6)/(x^3)]^(-4/5)
y' = (-4/5)[(8x-x^6)/(x^3)]^(-9/5) * -(3x^5+16)/x^3
You can massage that to get the various forms shown here:
http://www.wolframalpha.com/input/?i=derivative+[%288x-x^6%29%2F%28x^3%29]^%28-4%2F5%29
y = [(8x-x^6)/(x^3)]^(-4/5)
y' = (-4/5)[(8x-x^6)/(x^3)]^(-9/5) * -(3x^5+16)/x^3
You can massage that to get the various forms shown here:
http://www.wolframalpha.com/input/?i=derivative+[%288x-x^6%29%2F%28x^3%29]^%28-4%2F5%29
0 answers