(s+6)^2 = 3/4
s+6 = ±√3/2
s = -6±√3/2
This is where it helps to keep track of things
s = -6 ± (√3/2)
NOT
s = (-6±√3)/2
so, putting it all over 2,
s = (-12±√3)/2
Solve. Express your answer as exact roots.
(s+6)^2 = 3/4
Sq root (s+6)^2 = +-sq root 3/4
(s+6) = sq root 3/ 2
s = -6 +- sq root 3
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2
(The answer according to the textbook is (-12 +- sq root 3)/2. What error have I made?)
Thank you
2 answers
Thank you!