Differentiate y=4^(3x^2)..

Question

i need to know the calculation step..thanks for the help....

Answer 1

What? You managed to do e^xlnx, and can't do this one?

y' = ln4 4^(3x^2) (6x)
ooh! Look, that's the same as ln(4^(6x)) 4^(3x^2)

Looks like d/dx a^u = ln(a^u') a^u
but probably better to leave it as lna a^u u'