f (x) = 6 x 2 sin(x)tan(x)
begin with
12 [ sin x d/dx (tan x) + tan x d/dx(sin x)]
Differentiate the following function.
f (x) = 6 x 2 sin(x)tan(x)
Where do I begin?
2 answers
Begin by factoring out the 12.
f'(x) = 12 d/dx (sin x tan x)
Then use the product rule
f'(x) = 12[tanx d/dx(sinx) + sinx d/dx(tanx)]
= 12 (tanx*cosx + sinx*sec^2 x)
= 12 (sinx + secx tanx)
Check my steps. I don't have my books handy.
f'(x) = 12 d/dx (sin x tan x)
Then use the product rule
f'(x) = 12[tanx d/dx(sinx) + sinx d/dx(tanx)]
= 12 (tanx*cosx + sinx*sec^2 x)
= 12 (sinx + secx tanx)
Check my steps. I don't have my books handy.
3 answers