Differentiate each function

a) y = -3x^2 + 5x - 4

b) f(x) = 6/x - 3/(x^2)

c) f(x) = (3x^2 - 4x)(x^3 + 1)

the answers i got for each was:

a) y'= -6x + 5

b) f'(x)= -6/x^2 + 6/x^3

c) f'(x)= 15x^4 + 6x - 16x^3 - 4

please double check and let me know if these are correct, thank you.

5 answers

All correct, well done!

thank you! can u help me on this question please

determine the coordinates of two points on the plane with equation 5x + 4y - 3z = 6

Any point on the plane will satisfy the equation.

Since there are three variables x,y and z, you can fix any two variables and solve for the third.

Example:
Assuming arbitrarily y=6, z=6
=>
5x+4(6)-3(6)=6
5x+24-18=6
5x=0
x=0
So (0,6,6) is a point on the plane.

thank you

You're welcome!