Question
Differentiate the function.
g(u) = sqrt(2)u+sqrt(7u)
g'(u)=?
g(u) = sqrt(2)u+sqrt(7u)
g'(u)=?
Answers
Can somebody get me started maybe with the first two steps and then from there Ill try finishing it and then come back on and post the answer I get.
when a is a constant, g'(au) = a g'
You know that if
y=2x, y'=2(1)
y=3x^7, y' = 3(7x^6)
The constant is just a multiplier, and carries through.
So, what you have is
g = √2 u + √7√u
You know that if
y=2x, y'=2(1)
y=3x^7, y' = 3(7x^6)
The constant is just a multiplier, and carries through.
So, what you have is
g = √2 u + √7√u
Related Questions
sqrt 6 * sqrt 8
also
sqrt 7 * sqrt 5
6.92820323 and 5.916079783
So you can see the steps...
I have a question if someone could help, please explain it.
Given b = -1 and h = -1, what is the...
Evaluate sqrt7x (sqrt x-7 sqrt7) Show your work.
sqrt(7)*sqrt(x)-sqrt(7)*7*sqrt(7)
sqrt(7*x)...
Hello! If you can help me with these 3 questions I would love it!
1. How do you simplify sqrt5 +...