Asked by Anonymous
                Differentiate the function: y=sqrt(xe)^x^2(x^2+1)^10
            
            
        Answers
                    Answered by
            Steve
            
    Hmmm. Kind of murky. In any case, it's just the chain and product rules.
y = √x e^(x^2) (x^2+1)^10
Recall that if y=uvw then
y' = u'vw + uv'w + uvw'
So, that would give us
y' = 1/(2√x) * e^(x^2) * (x^2+1)^10
+ √x * 2x e^x^2 * (x^2+1)^10
+ √x * e^x^2 * 10(x^2+1)^9*2x
= √x e^x^2 (x^2+1)^9 ((x^2+1)/(2x) + 2x(x^2+1) + 20x)
and you can massage that more if you like
If I got it wrong, then fix the syntax and show us whatcha got.
    
y = √x e^(x^2) (x^2+1)^10
Recall that if y=uvw then
y' = u'vw + uv'w + uvw'
So, that would give us
y' = 1/(2√x) * e^(x^2) * (x^2+1)^10
+ √x * 2x e^x^2 * (x^2+1)^10
+ √x * e^x^2 * 10(x^2+1)^9*2x
= √x e^x^2 (x^2+1)^9 ((x^2+1)/(2x) + 2x(x^2+1) + 20x)
and you can massage that more if you like
If I got it wrong, then fix the syntax and show us whatcha got.
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.