Let's denote the number of pants Dezeree can buy as \( p \). The cost of each pair of pants is $32.50. Since she has a gift card worth $200, we can represent this situation with the following equation:
\[ 32.50p = 200 \]
Now, we'll solve for \( p \):
\[ p = \frac{200}{32.50} \]
Calculating the right side:
\[ p = 200 \div 32.50 = 6.1538 \]
Since Dezeree cannot purchase a fraction of a pair of pants, we round down to the nearest whole number:
\[ p = 6 \]
This means she can buy 6 pairs of pants. Now let's check how much money she would spend if she buys 6 pairs:
\[ \text{Total cost} = 32.50 \times 6 = 195 \]
If she buys 6 pairs of pants, she spends $195, which is within her $200 gift card limit. If she tried to buy 7 pairs of pants, the cost would be:
\[ \text{Cost for 7 pairs} = 32.50 \times 7 = 227.50 \]
This is over the $200 limit and thus not a viable option.
Therefore, the value \( p = 6 \) is a viable solution because it allows Dezeree to buy pants while staying within her budget, leaving her with $5 remaining on the gift card.
To summarize:
The equation to represent this situation is \( 32.50p = 200 \). After solving, \( p = 6 \). This is because she can buy 6 pairs of pants for a total cost of $195, which is within her $200 budget.
1 answer