To determine how many pairs of pants Dezeree can buy and spend exactly $200, you can set up the equation as follows:
Let \( x \) be the number of pairs of pants Dezeree buys. Each pair of pants costs $32.50, so the total cost for the pants will be \( 32.50x \).
Since she wants to spend exactly $200, we can set up the equation:
\[ 32.50x = 200 \]
Now, let's solve for \( x \):
- Divide both sides of the equation by 32.50:
\[ x = \frac{200}{32.50} \]
- Calculate the right side:
\[ x = 200 \div 32.50 = 6.15384615384 \]
Since \( x \) represents the number of pairs of pants, it must be a whole number. Thus, we round down since Dezeree can only buy whole pairs of pants.
The maximum whole number of pairs she can buy is \( 6 \).
Now, let's calculate how much money she would spend if she buys 6 pairs of pants:
\[ 32.50 \times 6 = 195 \]
This means she would spend $195, and she would have:
\[ 200 - 195 = 5 \]
So, if she buys 6 pairs of pants, she will have $5 left over.
If she tries to buy 7 pairs of pants:
\[ 32.50 \times 7 = 227.50 \]
This amount exceeds $200, which means it’s not a viable option.
Conclusion
The maximum number of pairs of pants Dezeree can buy while spending exactly $200 is 6 pairs, allowing her to spend $195 and have $5 left over.