Let's analyze each equation step by step to determine the type of solution they have.
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Equation: \( 3x + 12 + x = 8 + 4 + x \)
Simplifying both sides:
- Left Side: \( 3x + x + 12 = 4x + 12 \)
- Right Side: \( 8 + 4 + x = 12 + x \)
Now we have: \[ 4x + 12 = 12 + x \]
Now, isolate \( x \): \[ 4x + 12 - x = 12 \implies 3x + 12 = 12 \] Subtract 12 from both sides: \[ 3x = 0 \implies x = 0 \]
Conclusion: This equation has one solution because when you solve for x, the result is \( x = 0 \).
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Equation: \( 4(x + 1) = 4x + 1 \)
Distributing on the left side:
- Left Side: \( 4x + 4 \)
- Right Side: \( 4x + 1 \)
So, we have: \[ 4x + 4 = 4x + 1 \]
Now, isolate terms involving \( x \): \[ 4x + 4 - 4x = 1 \implies 4 = 1 \]
This is a false statement. There are no values of \( x \) that can satisfy this equation.
Conclusion: This equation has no solution because you end up with a false statement - no value of x will make the equation true.
Summary:
- The first equation has one solution because when you solve for \( x \), the result is \( x = 0 \).
- The second equation has no solution because you end up with a false statement - no value of \( x \) will make the equation true.