First, that is not a graph.
Did you mean
y=+-sqrt(ax^2+bx+c?) if a>0, it is an ellipse, if a<0 it is a hyperbola.
So othewise, I don't know what you are asking. if b^2-4ac less than zero, then the roots are not in the real domain.
what kind of solution does ax^2 -bx + c = 0 have if b^2 - 4ac < 0
I think an ellipse.. is this correct?
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