Determine vector, parametric, and if possible, symmetric equations of the line through D(-4, 3, 6) and parallel to the z-axis.
Vector form:
<-4, 3, 6> + t<0, 0, 1>
Parametric:
x = -4
y = 3
z = 6 + t
Symmetric:
x = -4 , y = 3 , z - 6
Is this right?
2 answers
The symmetric one looks a bit off. You need an equation for z, but there's nothing to compare it to. Maybe in this case (only one nonzero deb=nominator) there is no symmetric form. See what google has to say.
How about [(z - 6) / 1]?
1 answer