Determine vector, parametric, and if possible, symmetric equations of the line through C(2, -2, 1) and parallel to the line with parametric equations x = -1 + 5t, y = 2 – t, z = 3 – 4t.

Answer 1

from the given parametric equation x = -1 + 5t, y = 2 – t, z = 3 – 4t
you know the direction vector is <5,-1,-4>

so simply edit it so it contains the new point C(2, -2, 1)

The rest is very straight forward.
Let me know what you get.