Determine three consecutive even integers where the product of the two smaller integers is 56 less than the product of the two larger numbers.

Answer 1

n , n+2 , n+4
n(n+2) + 56 = (n+2)(n+4)
n^2 + 2 n + 56= n^2 + 6 n + 8
4 n = 48
n = 12
12, 14, 16
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check
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168 = 224 - ?
56 sure enough