determine three consecutive even integers, if the square of the largest integer less the square of the middle integer is 20 less than the square of the smallest integer

Answer 1

so, if the numbers are x-2, x and x+2, we have
(x+2)^2 - x^2 = (x-2)^2 - 20
solve for x and you get -2,10
check:
12^2 - 10^2 = 8^2 - 20 -- yep
0^2 - 2^2 = (-4)^2 - 20 -- yep