Use the following relationship:
M1V1=M2V2
Where
M1=0.250M
V1=?
M2=0.135M
and
V2=200mL
Solve for V1:
V1=(M2/M1)*V2
This would be the volume if the mole ratio were a 1 mole to 1 mole ratio. However, you need two moles of KOH for 1 mole of H2SO4:
Multiply V1 by 2 to arrive at the answer.
Answer should contain three significant figures.
And no, the answer will be in mL, since it is asking you for volume.
Determine the volume of 0.250M KOH solution required to neutralize each of the following samples of sulfuric acid. 200mL of 0.135M H2SO4. I have gotten both 0.027 and 0.675. I thought it was mol/L. Please help!
1 answer
1 answer