Determine the value of b in the equation b3 = −216.

Question

Group of answer choices

b = 6

b = −6

b = −72

b = 72

Answer 1

To solve the equation \( b^3 = -216 \), we need to find the value of \( b \).

First, we can take the cube root of both sides:

\[ b = \sqrt[3]{-216} \]

We know that:

\[ -216 = - (6^3) = - (6 \times 6 \times 6) \]

So,

\[ \sqrt[3]{-216} = -6 \]

Therefore, the value of \( b \) is:

\[ b = -6 \]

The correct choice is:

b = −6