Determine the tension in a 40 cm long pendulum when a bob of mass 200g moving at 0.7 m.s is 15 degrees from the vertical?
6 answers
correction the velocity is 0.7 m/s
The tension in the string minus the weight component in the string direction equals the centripetal force.
T - M*g cos15 = M V^2/R
M = 0.200 Kg
R = 0.40 m
g = 9.8 m/s^2
V = 0.7 m/s
Solve for T.
T - M*g cos15 = M V^2/R
M = 0.200 Kg
R = 0.40 m
g = 9.8 m/s^2
V = 0.7 m/s
Solve for T.
would the radius be half of the 0.40m?
no radius is .4m.
Thank you!
Two blocks move along a linear path on a nearly frictionless air track. One block, of mass 0.120 kg, initially moves to the right at a speed of 4.90 m/s, while the second block, of mass 0.240 kg, is initially to the left of the first block and moving to the right at 7.40 m/s. Find the final velocities of the blocks, assuming the collision is elastic.
So what is the velocity of the 0.120 kg block and the0.240 kg block?
So what is the velocity of the 0.120 kg block and the0.240 kg block?