Determine the tension in a 40 cm long pendulum when a bob of mass 200g moving at 0.7 m.s is 15 degrees from the vertical?

Answer 1

correction the velocity is 0.7 m/s

Answer 2

The tension in the string minus the weight component in the string direction equals the centripetal force.

T - M*g cos15 = M V^2/R

M = 0.200 Kg
R = 0.40 m
g = 9.8 m/s^2
V = 0.7 m/s

Solve for T.

Answer 3

would the radius be half of the 0.40m?

Answer 4

no radius is .4m.

Answer 5

Thank you!

Answer 6

Two blocks move along a linear path on a nearly frictionless air track. One block, of mass 0.120 kg, initially moves to the right at a speed of 4.90 m/s, while the second block, of mass 0.240 kg, is initially to the left of the first block and moving to the right at 7.40 m/s. Find the final velocities of the blocks, assuming the collision is elastic.
So what is the velocity of the 0.120 kg block and the0.240 kg block?