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Determine the number of moles of N atoms in 43.5 g of Mg(NO3)2.

Textbook answer: 1.43 mol N

My answer:
43.5 g Mg(NO3)x x (1 mol Mg(NO3)2/148.313 g Mg(NO3)2) x (2 mol N/1 mol Mg(NO3)2) = .293

Can tell me where i went wrong?

1 answer

I don't see anything wrong except you didn't multiply the 0.293 by 2 to get 0.587. I think the book answer is not right. Your factors are ok. The molar mass of Mg(NO3)2 is correct. Perhaps another tutor will see something wrong but I believe the book answer of 1.43 is incorrect.
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