Determine the number of moles of
a) N atoms in a sample of C7H5(NO2)3 that has the same number of O atoms as 12.6g C6H12O6
Someone posted a way to answer this question but i still don't understand
6 answers
And you may not understand the way I do it either. Instead of us posting until you do, why don't you post how it should be worked and tell us, in detail, what you don't understand about it.
i figured i would find the number of moles of oxygen from 12.6g of C6H12O6, after that i get lost
So let us see that figuring.
ok the molar mass of C6H1206 IS
6(12.01)+ 12(1.008)+ 6(16.00) = 180.16
THEN FIND THE MOLE
n=m/M = 12.6/180.16 = 0.0699
so the number of 0 atoms is
6 x 0.0699 = 0.4194
I don't know what next
6(12.01)+ 12(1.008)+ 6(16.00) = 180.16
THEN FIND THE MOLE
n=m/M = 12.6/180.16 = 0.0699
so the number of 0 atoms is
6 x 0.0699 = 0.4194
I don't know what next
ok the molar mass of C6H1206 IS
6(12.01)+ 12(1.008)+ 6(16.00) = 180.16
THEN FIND THE MOLE
n=m/M = 12.6/180.16 = 0.0699
OK to here
so the number of 0 atoms is
6 x 0.0699 = 0.4194
# O atoms is 6 x 0.0699 x 6.022 x 10^23 since there are 6.022 x 10^23 atoms in a mole of atoms.
I don't know what next
6(12.01)+ 12(1.008)+ 6(16.00) = 180.16
THEN FIND THE MOLE
n=m/M = 12.6/180.16 = 0.0699
OK to here
so the number of 0 atoms is
6 x 0.0699 = 0.4194
# O atoms is 6 x 0.0699 x 6.022 x 10^23 since there are 6.022 x 10^23 atoms in a mole of atoms.
I don't know what next
u is idiot