Determine the number of grams of Potassium Iodate present in 10.0 g of a 0.267 m Potassium Iodate solution.
3 answers
Is the m or M?
it says "m" but I am not sure that is right.
OK, we'll assume that is m and 0.267 molal KIO3.
0.267m means 0.267 mols KIO3/1000 g solvent.
0.267 mols KIO3 x molar mass KIO3 = grams KIO3 = approx 57 g but you need to that more accurately as well as the calculations that follow.
Then total solution is g KIO3+ 1000g solvent = 1000 + about 57 = about 1057g so in essence we have
57g KIO3/1057 g solution. You want 10 g of that so g KIO3 in 10 g is
about 57 x (10/1057) = ? g KIO3 in 10 g of 0.267 m KIO3.
0.267m means 0.267 mols KIO3/1000 g solvent.
0.267 mols KIO3 x molar mass KIO3 = grams KIO3 = approx 57 g but you need to that more accurately as well as the calculations that follow.
Then total solution is g KIO3+ 1000g solvent = 1000 + about 57 = about 1057g so in essence we have
57g KIO3/1057 g solution. You want 10 g of that so g KIO3 in 10 g is
about 57 x (10/1057) = ? g KIO3 in 10 g of 0.267 m KIO3.
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