To find the missing value that would make the equation have zero solutions, we need to set the equation equal to 0 and solve for x.
2(6x + 7) = 3x +___x + 14
12x + 14 = 3x + ___x + 14
Combine like terms:
12x = 3x + ___x
We can see that for there to be zero solutions, the coefficient of x on the left side (12x) must be different from the combined coefficient of x on the right side (3x + ___x). In other words, the coefficient of x on the right side must be -12x.
Therefore, the missing value is -12.
Determine the missing value that would make this equation have zero solutions.
2 (6x + 7) = 3x +___x + 14
5 answers
thats wrong
Apologies for the incorrect response. Let's try solving the equation correctly:
2(6x + 7) = 3x + ___x + 14
Expand the left side of the equation:
12x + 14 = 3x + ___x + 14
Combine like terms:
12x = 3x + ___x
To make the equation have zero solutions, we need the coefficient of x on the left side (12x) to be equal to the combined coefficient of x on the right side (3x + ___x). In other words, the missing value for the equation to have zero solutions is -3.
Therefore, the correct missing value is -3.
2(6x + 7) = 3x + ___x + 14
Expand the left side of the equation:
12x + 14 = 3x + ___x + 14
Combine like terms:
12x = 3x + ___x
To make the equation have zero solutions, we need the coefficient of x on the left side (12x) to be equal to the combined coefficient of x on the right side (3x + ___x). In other words, the missing value for the equation to have zero solutions is -3.
Therefore, the correct missing value is -3.
Determine the missing values that would make this equation have infinite solutions.
2 (6x + 7) = 3x +___x +___
2 (6x + 7) = 3x +___x +___
To find the missing values that would make the equation have infinite solutions, we need the coefficients of x on both sides of the equation to be equal.
2(6x + 7) = 3x +___x +___
Expanding the left side, we get:
12x + 14 = 3x +___x +___
Combining like terms, we have:
12x = 3x + ___x + ___
To have infinite solutions, the coefficient of x on the left side (12x) must be equal to the combined coefficient of x on the right side (3x + ___x). Similarly, the missing values must be such that when added to 3x, they give us a total of 12x.
Since we want the equation to have infinite solutions, any value for the missing coefficients would work as long as they sum up to 12. For example, we can choose -9 and -3, so that:
12x = 3x + (-9)x + (-3)x
12x = 12x
This equation would have an infinite number of solutions.
Therefore, the missing values that would make this equation have infinite solutions are -9 and -3.
2(6x + 7) = 3x +___x +___
Expanding the left side, we get:
12x + 14 = 3x +___x +___
Combining like terms, we have:
12x = 3x + ___x + ___
To have infinite solutions, the coefficient of x on the left side (12x) must be equal to the combined coefficient of x on the right side (3x + ___x). Similarly, the missing values must be such that when added to 3x, they give us a total of 12x.
Since we want the equation to have infinite solutions, any value for the missing coefficients would work as long as they sum up to 12. For example, we can choose -9 and -3, so that:
12x = 3x + (-9)x + (-3)x
12x = 12x
This equation would have an infinite number of solutions.
Therefore, the missing values that would make this equation have infinite solutions are -9 and -3.
1 answer