To have an infinite amount of solutions, the equation must be true for any value of x. This means the coefficients of x on both sides of the equation must cancel out.
In the given equation, we have:
2(6x + 7) = -4x + mx + nx
Expanding the left side of the equation:
12x + 14 = -4x + mx + nx
For the x terms to cancel out, the coefficient of x on the right side (-4x + mx + nx) must be equal to the coefficient of x on the left side (12x).
This means:
-4 + m + n = 12
To have an infinite amount of solutions, any values for m and n can be chosen as long as their sum equals 16.
For example, one possible solution is:
m = 9
n = 7
Thus, the missing values that would make this equation have an infinite amount of solutions are:
-4x + 9x + 7x
Determine the missing values that would make this equation have infinite amount of solutions. Both answers will be integers.2(6x+7)=−4x+ _ x+_
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