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Determine the mass in grams of ammonium chloride, NH4CI, required to prepare 0.250 L of a 0.35 M solution of ammonium chloride.

*NH4CI molar mass is 53.5 g
4.7 g
0.002 g
0.089 g
12.1 g

1 answer

12.1 g

The mass in grams of ammonium chloride required can be calculated using the formula:

mass = moles x molar mass

First, calculate the moles of NH4Cl:
moles = Molarity x Volume
moles = 0.35 mol/L x 0.250 L
moles = 0.0875 mol

Next, calculate the mass:
mass = 0.0875 mol x 53.5 g/mol
mass = 4.689 g

Therefore, the mass in grams of ammonium chloride required is 4.7 g.