5% SO4 w/w = 5g SO4/100 g solution.
(x g solute/1200) = 0.05
Solve for x g SO4^2- and convert to g K2SO4, then to mols K2SO4.
2. 3.6 what?
3. See 2.
How many moles of potassium sulfate would you need to prepare 1200 grams of 5.0% sulfate (m/m) solution?
Calculate the volume of solution of 3.6 NH4CI needed to prepare 350.0ml of 1.24 M NH4CI.
How many grams of ammonium chloride are in the solution you created in the above problem.
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