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Determine the coordinates of the point(s) on f(x) = x^3 - 2x^2 where the tangent line(s) are perpendicular to y-x+2=0.

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y-x+2=0 has a slope of 1, so you want lines with slope = -1.
f'(x) = 3x^2-4x
so now solve
3x^2-4x = -1
and find f(x) at those points

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