Determine the coordinates of the point on the graph of f(x)=3x^2-7x+4 where the tangent line is parallel to the line 5x+y=3

3 answers

line is
y = -5 x + 3
so slope = -5 = slope of tangent

f' = slope = 6 x - 7
where is that -5?
6 x - 7 = -5
6 x = 2
x = 1/3
so
y = 3(1/9) -7(1/3) + 4
is that 1/9 or 1/3
1/9, since it's 3x^2

don't you read your own equations?