[mass Fe x specific heat Fe x (Tf-Ti)] + [mass ice x heat fusion] + [mass H2O from melted ice x specific heat water x (Tf-Ti)] = 0
Tf = final T
Ti = initial T
Solve for mass Fe; that's the only unknown.
Determine mass of iron heated to 85.0 degrees C to add to 54.0 g of ice to produce water at 12.5 degrees C. The specific heat of iron is 0.045 J/g C.
1 answer
1 answer