heatgainedbyiron+heatgained by water+heatgainedmelting ice=0
Some of these will be negative (heat lost)
massiron*ciron*(12.5-85)+54*cwater*(12.5-0)+54*hfusionice=0
solve for mass of iron.
Determine the mass of iron heated to 85 Celsius to add to 54.0g of ice to produce water at 12.5 Celsius. The speciic heat of iron is 0.045J/g C
What steps do I take to solve this problem? Thanks
2 answers
the answer by bobpursley is incorrect.
the correct answer is 6377.4g
the correct answer is 6377.4g
1 answer