To determine if the point (3, 8) is a solution to the simultaneous inequalities \( y > x + 5 \) and \( y \leq 6x - 3 \), we need to check each inequality:
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For the inequality \( y > x + 5 \):
- Substitute \( x = 3 \) and \( y = 8 \): \[ 8 > 3 + 5 \implies 8 > 8 \] This is not true because 8 is not greater than 8.
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For the inequality \( y \leq 6x - 3 \):
- Substitute \( x = 3 \) and \( y = 8 \): \[ 8 \leq 6(3) - 3 \implies 8 \leq 18 - 3 \implies 8 \leq 15 \] This is true because 8 is less than or equal to 15.
Based on this analysis:
- The point (3, 8) is not a solution for the first inequality \( y > x + 5 \).
- The point (3, 8) is a solution for the second inequality \( y \leq 6x - 3 \).
Therefore, the correct response is:
No, it is in the solution set for \( y \leq 6x - 3 \), but on the line for \( y > x + 5 \).