4 answers
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To determine if the point (3, 8) is a solution to the simultaneous inequalities y > x + 5 and y <= 6x - 3, we need to substitute the values of x and y into both inequalities and check if the inequalities hold true.
First, let's substitute x = 3 and y = 8 into the inequality y > x + 5:
8 > 3 + 5
8 > 8
The inequality is not true, so the point (3, 8) is not in the solution set for y > x + 5.
Next, let's substitute x = 3 and y = 8 into the inequality y <= 6x - 3:
8 <= 6(3) - 3
8 <= 18 - 3
8 <= 15
The inequality is true, so the point (3, 8) is in the solution set for y <= 6x - 3.
Therefore, the correct answer is: No, it is in the solution set for y <= 6x - 3 but on the line for y > x + 5.