To determine if the point (3, 8) is a solution to the simultaneous inequalities, we will substitute x = 3 and y = 8 into both inequalities and see if the point satisfies each one.
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For the inequality \( y > x + 5 \): \[ 8 > 3 + 5 \implies 8 > 8 \] This inequality is not satisfied because 8 is not greater than 8.
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For the inequality \( y \leq 6x - 3 \): \[ 8 \leq 6(3) - 3 \implies 8 \leq 18 - 3 \implies 8 \leq 15 \] This inequality is satisfied because 8 is indeed less than or equal to 15.
Now, let's summarize:
- The point (3, 8) does not satisfy the first inequality \( y > x + 5 \).
- The point (3, 8) does satisfy the second inequality \( y \leq 6x - 3 \).
Thus, the correct response is: No, it is in the solution set for \( y \leq 6x - 3 \), but on the line for \( y > x + 5 \).