To determine if the point (3, 8) is a solution to the simultaneous inequalities \( y > x + 5 \) and \( y < 6x - 3 \), we need to evaluate both inequalities with \( x = 3 \) and \( y = 8 \).
1. For the first inequality \( y > x + 5 \):
- Substitute \( x = 3 \):
\[
y > 3 + 5
\]
\[
y > 8
\]
Here, \( 8 > 8 \) is **false** since it does not satisfy the strict inequality.
2. For the second inequality \( y < 6x - 3 \):
- Substitute \( x = 3 \):
\[
y < 6 \cdot 3 - 3
\]
\[
y < 18 - 3
\]
\[
y < 15
\]
Here, \( 8 < 15 \) is **true**.
Since the point (3, 8) does not satisfy the first inequality but does satisfy the second, it is not a solution to the simultaneous inequalities.
Thus, the correct response is:
**b No, it is in the solution set for y < 6x - 3, but on the line for y > x + 5.**