To determine if the point (3, 8) is a solution to the simultaneous inequalities \( y > x + 5 \) and \( y < 6x - 3 \), we need to evaluate both inequalities with \( x = 3 \) and \( y = 8 \).
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For the first inequality \( y > x + 5 \):
- Substitute \( x = 3 \): \[ y > 3 + 5 \] \[ y > 8 \] Here, \( 8 > 8 \) is false since it does not satisfy the strict inequality.
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For the second inequality \( y < 6x - 3 \):
- Substitute \( x = 3 \): \[ y < 6 \cdot 3 - 3 \] \[ y < 18 - 3 \] \[ y < 15 \] Here, \( 8 < 15 \) is true.
Since the point (3, 8) does not satisfy the first inequality but does satisfy the second, it is not a solution to the simultaneous inequalities.
Thus, the correct response is:
b No, it is in the solution set for y < 6x - 3, but on the line for y > x + 5.