To determine if the point (3, 8) is a solution to the simultaneous inequalities \( y > x + 5 \) and \( y \leq 62 - 3 \), we will evaluate each inequality separately.
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Check the first inequality:
\( y > x + 5 \)
Substitute \( x = 3 \) and \( y = 8 \):
\( 8 > 3 + 5 \)
\( 8 > 8 \)
This is false. (The inequality does not include the equal sign, so 8 is not greater than 8.) -
Check the second inequality:
\( y \leq 62 - 3 \)
Simplify \( 62 - 3 \) to get 59. So the inequality becomes \( y \leq 59 \).
Substitute \( y = 8 \):
\( 8 \leq 59 \)
This is true.
The point (3, 8) is not a solution to the first inequality (it lies on the line, but does not satisfy the strict inequality) but satisfies the second inequality.
Thus, the correct conclusion is: No, it is not in the solution set for either inequality.
The correct response is: No, it is in the solution set for \( y \leq 59 \), but on the line for \( y > x + 5 \).