To determine if the point (3, 8) is a solution to the simultaneous inequalities \( y > x + 5 \) and \( y \leq 6x - 3 \), we need to test the point against both inequalities.
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Test the first inequality \( y > x + 5 \):
- Substitute \( x = 3 \) and \( y = 8 \): \[ 8 > 3 + 5 \] \[ 8 > 8 \]
- This statement is false because \( 8 \) is not greater than \( 8 \). Therefore, the point (3, 8) does not satisfy the first inequality.
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Test the second inequality \( y \leq 6x - 3 \):
- Substitute \( x = 3 \) and \( y = 8 \): \[ 8 \leq 6(3) - 3 \] \[ 8 \leq 18 - 3 \] \[ 8 \leq 15 \]
- This statement is true. The point (3, 8) satisfies the second inequality.
Since the point (3, 8) does not satisfy the first inequality but satisfies the second, it is not a solution to the simultaneous inequalities.
Therefore, the correct response is: No, it is not in the solution set for either inequality.