Determine if function is even, odd, or neither...

f(x) = secx tanx

I understand how to find if its even or odd, but the sec and tan, I don't understand.
Can someone help?

1 answer

Isn't sec even (reciprocal of cosine). And Tan is odd, so the product is...

You can also graph it on your graphical calc.
Similar Questions
  1. Evaluate the integral of(secx)^2 * (tanx)^3 *dx I started out with letting u=secx and du=secx*tanx*dx , but then I am kind of
    1. answers icon 1 answer
  2. tan(3x) + 1 = sec(3x)Thanks, pretend 3x equals x so tanx + 1 = secx we know the law that 1 + tanx = secx so tanx + 1 becomes
    1. answers icon 0 answers
  3. How do you verify:1.) sinxcosx+sinx^3secx=tanx 2.) (secx+tanx)/(secx-tan)=(secx+tanx)^2 I tried starting from the left on both
    1. answers icon 0 answers
  4. I can't find the integral for(tanx)^(6)*(secx)^(2) I tried splitting up tanx into (tanx)^2*(tanx)^4 and let the latter equal
    1. answers icon 0 answers
more similar questions