Determine for what value(s) of d the quadratic equation 5x^2-10x+d = 0 has

Question

i) real and distinct roots
ii)real and equal roots
iii)non-real roots

This is what I did to solve for A.

5x^2-10x+d = 0
b^2-4ac = 0
(-10)^2-4(5)(d) = 0
100-20d = 0
-20d = -100
d = 5

Need help with others.

Answer 1

Close. Actually, you solved for (ii).

i) D > 0
100 - 20d > 0
d < 5

ii) D=0
100-20d = 0
d = 5

iii) D < 0
100-20d < 0
d > 5