For quadraic equation:
a x² + b x +c
∆ = b² - 4 a c
is the discriminant
The discriminant is used to determine the number of solutions in the quadratic equation.
There are three cases:
If ∆ < 0 the equation has two conjugate complex solutions
If ∆ = 0 the equation has one real solution
If ∆ > 0 the equation has two non-real (conjugate complex solutions)
In this case:
x² + 3 x + 5
The coefficients are:
a = 1 , b = 3 , c = 5
∆ = b² - 4 a c = 3² - 4 ∙ 1 ∙ 5 = 9 - 20 = - 11
∆ < 0
So the equation x² + 3 x + 5 has two non-real (conjugate complex solutions).
For the quadratic equation x squared plus 3 x plus 5 equals 0, find the value of the discriminant to determine if the equation has a real or non-real solution.
2 answers
My typo.
If ∆ < 0 the equation has two non-real (conjugate complex solutions)
If ∆ = 0 the equation has one real solution
If ∆ > 0 the equation has two real solutions
If ∆ < 0 the equation has two non-real (conjugate complex solutions)
If ∆ = 0 the equation has one real solution
If ∆ > 0 the equation has two real solutions