Asked by Rob
Determine algebraically whether the function f(x)=2x^42x^2 2x+1 is odd, even or neither.
Answers
Answered by
Jai
Even: Algebraically, we substitute x as -x and if it goes back to original function, then it's even. Thus, f(-x) = f(x).
Visually, if this function is graphed and you see that it is symmetric to y-axis, then it's even.
Odd: If f(-x) = -f(x).
I will assume the function you wrote is
f(x) = 2x^4 + 2x^2 + 2x + 1
Let x be -x.
f(x) = 2(-x)^4 + 2(-x)^2 + 2(-x) + 1
f(x) = 2x^4 + 2x^2 - 2x + 1
The resulting function is neither odd or even, since it didn't result in f(x) or -f(x).
Visually, if this function is graphed and you see that it is symmetric to y-axis, then it's even.
Odd: If f(-x) = -f(x).
I will assume the function you wrote is
f(x) = 2x^4 + 2x^2 + 2x + 1
Let x be -x.
f(x) = 2(-x)^4 + 2(-x)^2 + 2(-x) + 1
f(x) = 2x^4 + 2x^2 - 2x + 1
The resulting function is neither odd or even, since it didn't result in f(x) or -f(x).
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