Question
Algebraically determine the value(s) of x: log9(x-5)=1-log9(x+3)
Please help me. Thanks!
Please help me. Thanks!
Answers
Reiny
log9(x-5)=1-log9(x+3)
log9[(x-5)(x+3) =
(x-5)(x+3) = 9^1
x^2 - 2x - 24 = 0
(x-6)(x+4) = 0
x = 6 or -4
but x=-4 would be give an undefined result in the original, so
x = 6
log9[(x-5)(x+3) =
(x-5)(x+3) = 9^1
x^2 - 2x - 24 = 0
(x-6)(x+4) = 0
x = 6 or -4
but x=-4 would be give an undefined result in the original, so
x = 6