Describe how you would prepare 500 mL of a 0.10 M solution of HCl from a 12.0 M solution of HCl.
3 answers
Combine 4 and 1/6 mL of the 12 M solution with 495 and 5/6 mL of water.
Practically this is right; technically it is not.
Technically, the volumes are not additive; therefore, what you do is pipet 4 and 1/6 mL of the 12 M into a 500 mL volumetric flask and add enough water to make exactly 500 (fill to the mark of the flask). That way you KNOW you have a final volume of 500 mL.
Technically, the volumes are not additive; therefore, what you do is pipet 4 and 1/6 mL of the 12 M into a 500 mL volumetric flask and add enough water to make exactly 500 (fill to the mark of the flask). That way you KNOW you have a final volume of 500 mL.
That's the same thing. You just measure the water with the first solution. :/
4 answers